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 Write a c program to find 1+1/2+1/3+1/4+...+1/n



#include <stdio.h>
#include <conio.h>

void main()
  {
	int n, j;
	long float sum = 0;
	clrscr();
	printf("Enter the value of n: ");
	scanf("%d", &n);
	for (j = 1; j <= n; j++)
	{
		sum = sum + 1 / (float)j;
	}
	printf("Answer %lf", sum);
	getch();
  }

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